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Ambiguous Case Problem (trig)?

Ambiguous Case Problem (trig)? Topic: Ambiguous case sine
April 19, 2019 / By Jami
Question: Given triangle ABC with sides of a = 6, b = 10 and measure of angle A = (in degrees, minutes, seconds) 31˚10', find the other sides (c) and other angle measures (B)(C) This IS an ambiguous case problem. 10 points for correct answer. Thanks
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Best Answers: Ambiguous Case Problem (trig)?

Ephah Ephah | 4 days ago
use sine rule 31.10 = 31.17 degrees a/sinA = b/sinB = c/sinC 6/sin(31.17) = 10/sin(B) 11.59 = 10/sinB sinB = 10/11.59 sin(B) = 0.86 B = 59.3 degrees so C = 180 - (A+B) = 180 -(31.17 + 59.3) = 89.53 now a/sinA = c/sinC 11.59 = c/sin(89.53) c = 11.59*sin(89.53) = 11.59 It is almost right angled triangle with c as hypotenuse
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We found more questions related to the topic: Ambiguous case sine


Ephah Originally Answered: Ambiguous case trigonometry help?
Hi, Let x = distance from A to directly under the satellite and 50 - x = distance from B to directly under the satellite. If h is the height to the satellite, then tan 87 = h/x and tan 84.2 = h/(50 - x) x tan 87 = h and (50 - x) tan 84.2 = h Since both equal h, then: x tan 87 = (50 - x) tan 84.2 x tan 87 = 50tan 84.2 - x tan 84.2 x tan 87 + x tan 84.2 = 50tan 84.2 x(tan 87 + tan 84.2) = 50tan 84.2 50tan 84.2 -------------------------- = x tan 87 + tan 84.2 x = 17.017 miles <==ANSWER distance along the ground from A to be underneath the satellite h = x tan 87 = 324.709 miles <==ANSWER height of satellite If you wanted the diagonal distance from A to the satellite, it is 325.155 miles <==ANSWER, diagonal distance from A to satellite I hope that helps!! :-)

Cindra Cindra
a thank you to unravel those issues is by using making use of the regulation of Sines to unravel for the sine of the unknown perspective, ?, say. For any answer to be achievable, we could have sin ? ? a million, so anticipate that it is so. on account that ? and ? ? ? have the comparable sine, computing ? from sin ? will many times produce 2 strategies. If the sine is a million, i.e., ? = ?/2, there's a different answer. additionally, one answer could be impossible because it may produce a triangle the sum of whose angles exceeds ?. In the two of those 2 circumstances, the answer is unique; in any different case, it rather is the ambiguous case. So, the ambiguous case is whilst the unknown perspective (Z on your case) does have 2 achievable values. on your problem we've x / sin X = z / sin Z ?sin Z = z sin X / x = 7.5 sin fifty 8?/9.3 = 0.6839 ?Z = 40 3.15? or 136.80 5?. on account that 136.80 5? + fifty 8? > one hundred eighty?, the 2nd answer is impossible and Z = 40 3.15?. So, your answer is actual.
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Babette Babette
try using this online calculator just plug in the values it should work. http://www.csgnetwork.com/trianglessacalc.html
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Babette Originally Answered: Question on ambiguous case triangle.please explain?
Just adding on the previous answer: Draw a triangle and make the angle A be the 60 degree angle, and the side opposite is 40cm. It doesn't matter how you label the other two sides, but let's make the side opposite the angle B be the 15cm side. now, using Law of Sines, you get that sin(60)/40 = sin(B)/15 Solve for sin(B): sin(B) = 15sin(60)/40 = 3sqrt(3)/16 Now, the angle B = arcsin(3sqrt(3)/16), in degrees = 18.951 degrees, or 19 if you wanna round. BUT Sine is positive in both Quadrants 1 and 2, so there are possible two answers. Angle B could be either 19 degrees or 180-19=161 degrees. However we can clearly see that B can't be 161 as 161+60 = 221 which is clearly more than 180 degrees which is the sum of the angles in a triangle. So there is only one solution of 19 degrees.

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