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Topic: **Case satellite****Question:**
As the satellite goes through the thin air at high altitudes loses mechanical energy, but does this result in an acceleration due to a smaller orbit or does this result in a deceleration?

June 25, 2019 / By Jaquelyn

The kinetic energy of the orbit is converted to thermal energy from heat brought about by air friction. This is due to the first law of thermodynamics. The first law in general states that energy can not be created or destroyed. It can only be changed from one form to another. In this case it is converted from the kinetic energy of the orbit, (ke=1/2mv^2) to thermal heat. This loss of energy reduces velocity. Any reduction of velocity over time is by definition deceleration.

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Did you like the answer? We found more questions related to the topic: **Case satellite**

There's a pretty simple answer. If A and B are the same substance, and A has a slightly higher temperature than B, but A has a much smaller mass than B, then B will have a larger internal energy. This is because temperature is an intensive property (independent of the amount of substance), while heat is an extensive property (proportional to the amount of substance). Same thing can happen if A and B are different substances, and A has a larger specific heat capacity than B. But I don't think that's what you meant. If A and B are the same substance with the same mass, and A has the higher temp, then A will always have the higher energy. Another small change to your statement. Heat is a measure of the kinetic energy of the atoms and molecules in a substance. There is no internal potential energy component to heat energy.

Well, temperature is the average kinetic energy of a substance. So one substance could have more energy than another, but it could be spread out more making the average energy lower (lower temperature). I guess this is possible.

Temperature is a measure of internal energy. If one body has a higher temperate, then it has a higher average (per particle) internal temperature. This says nothing about the energy of the body as a whole.

If I remember wisely, friction provides unfavourable acceleration interior the choice path. It could desire to alter kinetic capability because it adjustments speed. Does this answer your question?

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There are two forces that affect the block’s acceleration. The component of its weight that is parallel to the incline causes it to accelerate. The friction force causes it to decelerate. The net force on the block is the difference of these two forces. Force parallel = m * g * sin θ Ff = μ * m * g * cos θ Net force = m * g * sin θ – μ * m * g * cos θ a = g * sin θ – μ * g * cos θ a = g * (sin θ – μ * cos θ) The distance from point A to point B is s meters. Let’s use the following equation to determine its velocity as it passes point B. vf^2 = vi^2 + 2 * a * d, vi = 0 vf^2 = 2 * g * (sin θ – μ * cos θ) * s vf = √(2 * g * (sin θ – μ * cos θ) * s) KE = ½ * m * v^2 KE = ½ * m * 2 * g * (sin θ – μ * cos θ) * s

I just did it... the answer is KB = m g s sin θ − µ m g s cos θ I am not confused anymore. If delta E is equal to work and work is friction then friction is negative... trust me this is the answer. Also if you are helped by my answer GIVE ME POINTS!!!!!!!!

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