6928 Shares

# Homework help with ABSOLUTE VALUE INEQUALITIES.? Topic: Inequalities homework
July 20, 2019 / By Debra
Question: I can not get these right.. plus i dont know how to do them please help! |3x+4| +3 <_ 2 3|2x-7|+15 =6 2/3x+ 1/5= 2x= 3/10 2|1/3x-1| =0 1/2|4-5x| +5<12 |4a+7|-8 <_ 5 please helpp and thanks in advance :)! ## Best Answers: Homework help with ABSOLUTE VALUE INEQUALITIES.? Brittani | 3 days ago
You have to isolate the absolute value first and then split the equation. Sometimes it won't work. Like for instance the first one. |3x+4| +3 <_ 2 Subtract 3 from both sides. |3x+4| <_-1 Well an absolute value can never be less than -1, so no answer.
👍 234 | 👎 3
Did you like the answer? Homework help with ABSOLUTE VALUE INEQUALITIES.? Share with your friends

We found more questions related to the topic: Inequalities homework Originally Answered: Help on Absolute Value homework?
Ix+3I <1/2 Multiply both sides by 4: 4*Ix+3I < 4*(1/2) I4x+12I < 2 Add 1 to both sides: I4x +12I +1 < 2 + 1 Then I4x+13I < 3 Good luck! Originally Answered: Help on Absolute Value homework?
First multiply each side by 4 and get: |4x + 12| < 4(1/2) = 2 That is |4x+12| <2 Now add 1 to both side and get: |4x +13| < 3 OK! Originally Answered: 05.01 Solving Inequalities?
1.) x-3 > -9 Add the opposite of - 3 to both side. x > -6 The circle would be open on the graph. 2.) -2x + 1 ≤ -11 subtract 1 from both sides. -2x ≤ -12 divide -2 from both sides. The sign needs to be changed since you're dividing by a negative. x ≥ 6 The circle would be closed on the graph. 3.) 10 < -3x + 1 subtract 1 from both sides. 9 <-3x Divide -3 from both sides. The sign needs to be changed since you're dividing by a negative. -3 > x The circle would be open. 4.) 2(x + 5) > 8x - 8 Use distributive property. 2x + 10 > 8x - 8 Add 8 to both sides 2x + 18 > 8x Subtract 2x 18 > 6x 3 > x The circle would be open. 5.) -2(x-3) ≥ 5 - (x+3) apply distributive property. -2x +6 ≥ 5 -x -3 Subtract 5 from both sides. -2x + 1 ≥ -x - 3 Add 2x. 1 ≥ 1x - 3 add 3 4 ≥ 1x divide by 1 4 ≥ x Circle is closed. 6.) You would use a closed circle if the sign is greater/ less than or equal to. Open circle would be if the sign is greater/ less than. You would shade to the left if x is less than the number. You would shade right if x is greater than the number. Ex. 3 > x (You would shade to the left.) 7.) Inequalities can be used to describe temperature or even golf scores. Originally Answered: 05.01 Solving Inequalities?
I shall only do #1 so you can do it yourself because you should be able to do your own work. x -3>9 so treat > like it is = so like x-3=9. How do you solve your algebra? You take away like terms from either side to find x. So, when treating it like an equation, x-3=9 would make x=12. Replace the = with > and you've got x>12 or x is greater than 12. Since the inequality is just > and not > with a line under it meaning >or=, we use an open circle to distinguish that it can't encompass/include 2. And then you would shade in the direction of the arrow, so since the arrow is pointing right, you would shade right. Hope this helps! Get your work done! Originally Answered: 05.01 Solving Inequalities?